[Python] How to use the cl command?

All, I found a piece of information on how to call c files in python, in these examples: there is a c file, which includes many other header files, the very beginning of this c files is #include Python.h, then I found that #include Python.h actually involves many many other header files, such as pystate.h, object.h, etc, so I include all the required header files. In an cpp IDE environment, it did not show errors. What I am trying to do is call this c code in python, so from ctypes import *, then it seems that a dll should be generated by code such as: cl -LD test.c -test.dll, but how to use the cl in this case? I used the cygwin: gcc, it worked fine. Could anyone help me with this i.e.: Call the C in python? Do I make myself clear? Thank you in advance!!

Well, Now I feel it important to tell me what I did: The ultimate goal I wanna achieve is: I am lazy, I do not want to re-write those c codes in python, (which is very complicated for me in some cases), so I just want to generate dll files that python could call. I followed an example given by googleing "python call c", there are two versions in this examples: linux and windows: The example test.c:

#include <windows.h>
BOOL APIENTRY
DllMain(HANDLE hModule, DWORD dwReason, LPVOID lpReserved) {
return TRUE;
}
__declspec(dllexport) int
multiply(int num1, int num2) {
return num1 * num2;
}


Two versions: 1, Complie under linux

gcc -c -fPIC test.c
gcc -shared test.o -o test.so


I did this in cygwin on my vista system, it works fine;

2, Compile under windows:

cl -LD test.c -test.dll


I used the cl in windows command line prompt, it won't work!

These are the python codes:

from ctypes import *
import os
libtest = cdll.LoadLibrary(os.getcwd() + '/test.so')
print test.multiply(2, 2)


Could anyone try this and tell me what you get? thank you!

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